E is a point inside square $ABCD$ such that $ECD = EDC = 15$...
Jun 18, 2020 · E is a point inside square ABCD such that $\angle {ECD} = \angle {EDC} = 15.$ Find $\angle {AEB}.$ I drew a picture for this but I don't know how to continue. Any ...
geometry - Pentagon $ (ABCDE)$ is inscribed in a circle of radius …
Jul 19, 2024 · Pentagon $ (ABCDE)$ is inscribed in a circle of radius $1$. If $\angle DEA=\angle EAB = \angle ABC$ and $m\angle CAD=60^ {\circ}$ and $BC=2AB$. Compute the area of ...
Show that $ e^{A+B}=e^A e^B$ - e^ {A+B}=e^A e^B
As a remark, it is actually legitimate to assume that A A and B B are simultaneously diagonalisable (surprise, surprise!), so the proposition is trivial. But obviously, the reason why …
geometry - Prove that triangle $EDC$ is similar to triangle $EAB ...
Jun 11, 2023 · Prove that triangle $EDC$ is similar to triangle $EAB$, given $CD$ is parallel to $AB$, and specify a reason for similarity. I deduce that triangles $ACE$ and $CDE$ have …
When does $ (e^a)^b = e^ {ab}$ hold? - Mathematics Stack …
For a complex number $A$ and a real number $B$, when does the well-known formula $(e^A)^B = e^{AB}$ fail? Or does it hold at all for complex A? Since $e^{2\\pi i} = 1 ...
Prove that 5 lines are concurrent, and find the expression for the ...
Sep 22, 2020 · So we take the lines from centroids of $\triangle CDE, \triangle DEA, \triangle EAB$ through point $\overline {p}$ and show each of them is perpendicular to the line …
geometry - 5 triangles with the same area inside a pentagon ...
Feb 1, 2017 · A pentagon ABCDE contains 5 triangles whose areas are each one. The triangles are ABC, BCD, CDE, DEA, and EAB. Find the area of ABCDE? Is there a theorem for ...
Area of Pentagon using geometry - Mathematics Stack Exchange
Apr 5, 2017 · A given convex pentagon $ABCDE$ has the property that the area of each of the five triangles $ABC$, $BCD$, $CDE$, $DEA$, and $EAB$ is unity. calculate the area of the ...
Proof that $e^{ab} = \\left(e^a\\right)^b$, using the series for $e^x$
He’s specifically trying to show it for $e$ using the series expansion.
If $AB = I$ then $BA = I$ - Mathematics Stack Exchange
Sep 2, 2010 · If $A$ and $B$ are square matrices such that $AB = I$, where $I$ is the identity matrix, show that $BA = I$. I do not understand anything more than the following ...